逢甲學報, Band 13逢甲大學, 1980 |
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... all AE S ) then this minimum is unique . Proof : Suppose there are two such matrices B , and B. Then A≥B1 for all Ae S. Since BS , B2≥B1 . Likewise , B1B . From Lemma 2 , B1 = B2 . O. E. D. Let us return to consideration of the risk ...
... all AE S ) then this minimum is unique . Proof : Suppose there are two such matrices B , and B. Then A≥B1 for all Ae S. Since BS , B2≥B1 . Likewise , B1B . From Lemma 2 , B1 = B2 . O. E. D. Let us return to consideration of the risk ...