 RULE. — From half the sum of the three sides, subtract each side separately; multiply the half -sum and the three remainders together; the square root of the product is the area.  Commercial class book - Seite 158von Alfred Newsom Niblett - 1861Vollansicht - Über dieses Buch
 | Thomas Keith - 1810 - 478 Seiten
...these four logarithms, is the logarithmical sine of half the angle sought. (H. 215.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmica! co-secants of half the sum of the sides, and of the difference... | |
 | Andrew Mackay - 1811 - 162 Seiten
...easily measured by the above method. In this case, therefore, the three sides are to be measured. Now from half the sum of the th'ree sides, subtract each side separately; then extract the square root of the product of half the sum of the sides by the three differences ;... | |
 | Thomas Keith - 1826 - 504 Seiten
...these four logarithms, is the logarithmical sine of half the angle sought. (F. 184.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmical co-secants of half the sum of the sides, and of the difference... | |
 | John Gummere - 1828 - 404 Seiten
...and.48°15'? Ans. 6 A. 3R. 18 P. PROBLEM V. To find the. area of a triangle when the three sides are given. From half the sum of the three sides subtract each side severally; multiply the half sum and the three remainders continually together, and the square root... | |
 | Dudley Leavitt - 1830 - 154 Seiten
...the three sides of a triangle are given, the area may be found thus, without a perpendicular. Erom half the sum of the three sides, subtract each side separately ; multiply the half sum and 3 remainders continually together, and the square root of the last product will be the area. Therefore,... | |
 | Ira Wanzer - 1831 - 408 Seiten
...in Problem III. 2. When the three sides of the triangle are given, the area may be found as follows: From half the sum of the three sides subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root... | |
 | Ireland commissioners of nat. educ - 1834 - 370 Seiten
...feet Gi inches. PROBLEM V. Having the three sides of any Triangle given, to find its orea. RULE I. From, half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product... | |
 | John Hind - 1837 - 584 Seiten
...have the area - £ AB x CD C 2 = - x - \/s (s — «)(« — b) (s — c) From half the sum of the sides, subtract each side separately: multiply the half sum and the three remainders together, and the square root of the product will be the area. Ex. 4. Required the area of a triangle... | |
 | Commissioners of National Education in Ireland - 1837 - 284 Seiten
...feet 6^ inches. PROBLEM V. Having the three sides of any Triangle given, to find its area. RULE I. From half the sum of the three sides subtract each side separately, then multiply the half sum and the three remainders together, and the square root of the last product... | |
 | Thomas Keith - 1839 - 498 Seiten
...the sum of these four logarithms is the logarithmic sine of half the angle sought (422). RULE III. From half the sum of the three sides subtract each side separately. Then add together, mic sines of the difference between the half sum and each side containing the required... | |
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