 | Thomas Hunter - 1878 - 142 Seiten
...it 28 and 33J feet. Ans. 222^ yards. PROBLEM VT. To find the area of a trapezoid. RULE.—Multiply the sum of the parallel sides by the perpendicular...between them, and half the product will be the area.* 1. The parallel sides of a trapezoid are 750 and 1225, and the perpendicular distance between them... | |
 | 1878 - 534 Seiten
...tivo opposite sides of which are parallel. The content of a Trapezoid equals half the • product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which 5 and d are parallel; then, making... | |
 | Daniel Kinnear Clark - 1878 - 1022 Seiten
...contiguous sides by the natural sine of the included angle. To find the area of a trapczoid. Multiply half the sum of the parallel sides by the perpendicular distance between them. To find the area of a quadrilateral inscribed in a circle. From half the ;um of the four sides subtract... | |
 | Clement Mackrow - 1879 - 552 Seiten
...& = the perpendicular height, then A = ab. 2. Tofindtlie area of a trapezoid. (Fig. 68.) RULE. — Multiply the sum of the parallel sides \ by the perpendicular distance between them ; half j. the product will be the area. Thus if A = the ; area, J and a = the parallel si des, and... | |
 | Alfred Hiley - 1879 - 228 Seiten
...parallel sides by the perpendicular distance between them, and divide the product by 2. Or, multiply half the sum of the parallel sides by the perpendicular distance between them. •Note 1. — To find the sum of the parallel sides, when the area and the perpendicular distance... | |
 | William Mitchell Gillespie - 1880 - 540 Seiten
...figm«s, tiro opposite sides of which are parallel. The content of a Trapezoid equals half the product of the sum of the parallel sides by the perpendicular distance between them. If the given quantities are the four sides a, b, c, d, of which 4 and d are parallel ; then, making... | |
 | T W. Stone - 1881 - 134 Seiten
...side. For the right-angled parallelogram. Multiply one side, the larger, by the less. The trapezoid. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. The triangle. Multiply the base by the perpendicular, and half the product is the area.... | |
 | 1882 - 526 Seiten
...perpendicular distance betwcen the sides. V. To find the area of a trapezoid :— Multiply one half the sum of the parallel sides by the perpendicular distance between them.^ PROBLEMS. 1. In a farm 225 rods long and 145 rods wide are how many acres ? #. How many yards of carpeting... | |
 | Stephen Roper - 1884 - 740 Seiten
...the perpendicular height, and take half the product. To find the area of a trapezoid, multiply half the sum of the parallel sides by the perpendicular distance between them ; the product will be the area. To find the area of a quadrilateral inscribed in a circle. — From... | |
 | 1886 - 170 Seiten
...of acres in a quadrilateral, having two opposite sides parallel, (such is Fig. 2)— Multiply halt the sum of the parallel sides by the perpendicular distance between them, in rods, and divide the product by 160. EXAMPLE: Given a piece of land ABCE, (Fig. 2) with the side... | |
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RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
